Im working with HiveMq Client Mqtt3 for Android and when i called Flowable Subscribe function i receive a TimeOutException
I’ve tried to set timeOut property but without success.
I called connect().andThen(subscribeTopic().ignoreElements())
1 - Connect OK
2 - Subscribe OK but the subscription returned in onError() -> The source did not signal an event for 6 seconds and has been terminated.
Does anyone know how can avoid this exception? Because this stop the Thread and don’t execute another .andThen in sequence… Example: connect().andThen(subscribe()).andThen(disconnect())
Nice to see your interest in MQTT and the HiveMQ MQTT client.
Can you please share a more complete snippet of your code, as well as the error you are seeing?